[ts-7000] Re: explanation for DIO

["PeterElliot" <>]

Hi Manu,

Yes PBDR=0x30 would turn on both 4&5.

I made a typo on the Hex Bit list. It should be:

 Bit 0: = 0x01 HEX
 Bit 1: = 0x02 HEX
 Bit 2: = 0x04 HEX
 Bit 3: = 0x08 HEX
 Bit 4: = 0x10 HEX
 Bit 5: = 0x20 HEX 
 Bit 6: = 0x40 HEX  <- Not 0x30
 Bit 7: = 0x80 HEX  <- Not 0x40 Oops!

PJE

--- In  "ejeffredo" <> wrote:
>
> Dear Peter,
> 
> thanks for your reply, that clear.
> So if I want output 4 and 5 on, I write PBDR=0x30
> 
> Manu
> 
> 
> 
> 
> --- In  "PeterElliot" <egroups@> wrote:
> >
> > --- In  "ejeffredo" <ejeffredo@> wrote:
> > >
> > > Hi all,
> > > 
> > > I need some explanation for dio register. For example : 
> > > 
> > > PBDDR = 0xf0 means dio 0 to 3 : input and dio 4 to 7 : output
> > > PBDR = 0x01 : all dio =0 except dio 0 = 1
> > > 
> > > Thanks,
> > > 
> > > Manu
> > >
> > 
> > 
> > Hi Manu,
> > 
> > You need to be a bit more specific about your question. Looking at what you 
> > wrote (and not referencing anything else).
> > 
> > The digital I/O port (PB) above consists of two registers, the data 
> > direction register (PBDDR) which tells the port which of the eight bits are 
> > inputs (0) or outputs (1). The data is then read/written to the data 
> > register (PBDR), where reads from the register will read the inputs, and 
> > writes to the register set the state of the outputs.
> > 
> > In your above example:
> > 
> > Bit 0: = 0x01 HEX
> > Bit 1: = 0x02 HEX
> > Bit 2: = 0x04 HEX
> > Bit 3: = 0x08 HEX
> > Bit 4: = 0x10 HEX
> > Bit 5: = 0x20 HEX
> > Bit 6: = 0x30 HEX
> > Bit 7: = 0x40 HEX
> > 
> > Thus to set the data direction register for bits 4 to 7 to be outputs you 
> > add them up 0x10 + 0x20 + 0x40 + 0x80 = 0xF0.
> > 
> > The PBDR=0x01 does not match with the PBDDR setting above as the PBDR 
> > instruction is trying to write an output to a pin set as an input. More 
> > likely would be PBDR=0x10 which would set output 4 on.
> > 
> > Hope this makes things clearer.
> > 
> > PJE
> >
>




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