Dear Peter,
thanks for your reply, that clear.
So if I want output 4 and 5 on, I write PBDR=0x30
Manu
--- In "PeterElliot" <> wrote:
>
> --- In "ejeffredo" <ejeffredo@> wrote:
> >
> > Hi all,
> >
> > I need some explanation for dio register. For example :
> >
> > PBDDR = 0xf0 means dio 0 to 3 : input and dio 4 to 7 : output
> > PBDR = 0x01 : all dio =0 except dio 0 = 1
> >
> > Thanks,
> >
> > Manu
> >
>
>
> Hi Manu,
>
> You need to be a bit more specific about your question. Looking at what you
> wrote (and not referencing anything else).
>
> The digital I/O port (PB) above consists of two registers, the data direction
> register (PBDDR) which tells the port which of the eight bits are inputs (0)
> or outputs (1). The data is then read/written to the data register (PBDR),
> where reads from the register will read the inputs, and writes to the
> register set the state of the outputs.
>
> In your above example:
>
> Bit 0: = 0x01 HEX
> Bit 1: = 0x02 HEX
> Bit 2: = 0x04 HEX
> Bit 3: = 0x08 HEX
> Bit 4: = 0x10 HEX
> Bit 5: = 0x20 HEX
> Bit 6: = 0x30 HEX
> Bit 7: = 0x40 HEX
>
> Thus to set the data direction register for bits 4 to 7 to be outputs you add
> them up 0x10 + 0x20 + 0x40 + 0x80 = 0xF0.
>
> The PBDR=0x01 does not match with the PBDDR setting above as the PBDR
> instruction is trying to write an output to a pin set as an input. More
> likely would be PBDR=0x10 which would set output 4 on.
>
> Hope this makes things clearer.
>
> PJE
>
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