[ts-7000] Re: how do I synchronize two (or more) digital output pins

[" [ts-7000]" <>]

sbus_poke16(0x6c, sbus_peek16(0x6c) & ~(1 << pinOffSet));

  -Read 16 bits  IO ports
  -Create a mask to clear  the corresponding bit .     (1<< n) is equivalent to ( 2 power n)  and the ~ is the complement.
     Ex:     ~(1<<(31-21)) =  0xBFF
  -And write it back.

The best way to deal using  fast access with multiple unorder DIO pins is to create a complement Mask of all the DIO you want to manipulate and a Lookup Table with all the possibilities.

Using the complement mask to knock off DIO bits and the Table to set them will be very effective.

This is an example  for a 4 bits LCD display. The DIOs don’t need to be in sequence, it could be any DIO.
Ex:



#define  NUMBER_OF_DIO  4

// set the TABLE_SIZE  to   2 power DIO_NUMBER
#define TABLE_SIZE   16

// specify you DIO (from 21 to 36) . The first will be the LSB. 
int DIO[NUMBER_OF_DIO]= { 21,22,31,32};

unsigned short   Table[TABLE_SIZE];
unsigned short Mask;

void initTable(void)
{
  int loop;
  int bits;
  unsigned short _utemp;

  TableSize= pow(2,DIO_NUMBER);
  Table =  alloc(TableSize * sizeof(unsigned short);

  // now let’s create the table
  for(loop=0;loop<TABLE_SIZE;loop++)
  {
      utemp=0;      
      for(bits=0;bits<NUMBER_OF_DIO;bits++)
        if(loop & (1<<bits))
           utemp|= 1<< (DIO[bits]-21);
      Table[loop]=utemp;
  }

 // and the Mask;
 Mask = ~Table[TABLE_SIZE-1];
}

 

// This is the write function
void write4bits( unsigned char value)
{
  if(value>= TABLE_SIZE) return;
   sbus_poke16(0x6c, (sbus_peek16(0x6c) & Mask) | Table[value]);
}

This is just an example. 

Daniel

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