If you have two microphones as follows
Microphone one (M1) has a sensitivity of 13mV/pa
Microphone two (M2) has a sensitivity of 10mV/Pa
Formula is a 20xLog equation
(20 x log(M1/M2))
Therefore microphone two needs
(20 x Log(13/10)) =3D 2.2dB more gain to match microphone one
Note** This is straight out of Greg Simmons 'Microphones To Tibet' article =
in the Australian magazine 'Audio Technology' Issue 40
Regards
John
"While a picture is worth a thousand words, a
sound is worth a thousand pictures." R. Murray Schafer via Bernie Krause
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