**** Ah, yes. Oops. The correct formula SHOULD have been:
extraction = (oxygen in inspired air - oxygen in expired air)/oxygen in
inspired air
sorry for any confusion.... Mark C
>Thanks very much for this interesting and illuminating contribution to this
>increasingly scientific thread, Mark.
>One point: Is your "O2 Extraction" equation correct? As you have written
>it a more efficient animal (ie one which extracts a higher % of the
>available oxygen) would have a LOWER O2 Extraction, not higher. However,
>logical use of the concept of O2 extraction would have the figure higher in
>more efficient animals (as your figures suggest). Is the ratio in fact the
>REDUCTION in the O2 tension (or %) in expired air compared with inspired air??
>Cheers.
>Richard
>
> _____________________
>From: Dr Richard Nowotny,
> Melbourne, Australia.
> Tel. (w) 61-3-9214.1420
> <>
> _____________________
****************************************
Mark Chappell, Biology Department, UC Riverside
until Aug '99: C/O Dr. Bill Buttemer
Dept. Biological Sciences, University of Wollongong
Wollongong NSW 2522 AUSTRALIA
email:
web: http://cnas.ucr.edu/~bio/faculty/Chappell.html
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